from a distance of 1210 feet from a spotlight, the angle of elevation to a cloud base is 41°. Find the height of the cloud base to the nearest foot.
Use tangent: tan(angle) = opposite/adjacent
Here: tan(41°) = height/1210
so: height = 1210*tan(41°)
$${\mathtt{height}} = {\mathtt{1\,210}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{41}}^\circ\right)} \Rightarrow {\mathtt{height}} = {\mathtt{1\,051.836\: \!952\: \!757\: \!36}}$$
height = 1052 ft to the nearest foot.
.
Use tangent: tan(angle) = opposite/adjacent
Here: tan(41°) = height/1210
so: height = 1210*tan(41°)
$${\mathtt{height}} = {\mathtt{1\,210}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{41}}^\circ\right)} \Rightarrow {\mathtt{height}} = {\mathtt{1\,051.836\: \!952\: \!757\: \!36}}$$
height = 1052 ft to the nearest foot.
.