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From 2003 onward, the number of daily visitors to a website increased by 200% every two years. So, for example, the number of visitors in 2011 was 200% more than the number of visitors in 2009.

In what year was the number of daily visitors 800% more than the number of daily visitors in 2003?
 

Guest Sep 7, 2018
edited by Guest  Sep 7, 2018
edited by Guest  Sep 7, 2018
 #1
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Well this question is very odd if you think about it, since most people would say 2011 because it seems obvious. They would be wrong! This isn't the same as doubleing because you are not doing 200% + 200%, but instead it will be 200% * 400% so the answer to this problem is 2007 using our equation. Could I get confirmation?

OwenT154  Sep 7, 2018
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https://web2.0calc.com/questions/from-2003-onward-the-number-of-daily-visitors-to  this was a question from a while back. It might have a better explanation!wink

OwenT154  Sep 7, 2018
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Date            Increase          number of visitors            

2003                0                          N                           

2005                2N               N+2N = 3N                    

2007             2*3N = 6N      3N+6N = 9N                   

2009             2*9N = 18N    9N+18N = 27N             

2011             2*27N = 54N   27N+54N = 81N            

 

 

800% increase on N = 8N so total visitors would have been  N + 8N = 9N 

Hence year was 2007.

Alan  Sep 7, 2018
edited by Alan  Sep 7, 2018
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@200% 1 becomes 3 every 2 years. And:
@800% 1 becomes 9 every n years
The year to year inctrease =3^1/2 =sqrt(3) - 1 x 100 =73.20% annual comp.rate.
9 = 1 x [1 + .732]^n
n =Log(9) / Log(sqrt(3))
n = 4 Years, or 2003 + 4 = 2007.

Guest Sep 7, 2018

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