+1418 Find the total surface area and the volume of the conical frustum below.
+129771 L = sqrt [ 92^2 + (33-25)^2] = sqrt [ 92^2 + 8^2] = 4sqrt [533]
R = 33
r =25
Surface area = pi L (R + r) + pi (R^2 + r^2) = pi [ 4sqrt (533) ](58) + pi ( 33^2 + 25^2) ≈ 22211.49 units^2
S1 = pi * 33^2 S2 = pi * 25^2 H = 92
Volume = H/3 * ( S1 + S2 + sqrt [ S1 * S2 ]) =
92/3 * ( pi (33^2 + 25^2) + sqrt [ pi*33^2 * pi* 25^2 ] ) ≈ 244612.78 units^3
