+0

# REPOST:

+10
719
21
+4682

REPOST:

I had this posted before but i deleted it as no one was online.

GOAL:

Your Goal is to make all nine expressions equal six using three numbers starting  with 3, 1's, to 3, 9's.

DISPLAY:

1 1 1= 6

2 2 2 = 6

3 3 3 = 6

4 4 4= 6

5 5 5 = 6

6 6 6 = 6

7 7 7 = 6

8 8 8 = 6

9 9 9 = 6

RULES:

.You can only put in maths symbols that don't include numbers (E.G Powers are NOT allowed)

.If you have finished comment that you're done no you're answer as it could spoil for others

NOTE:

.There are more than one answer

.CPhill started this on the last post and completed it :)

QUESTION:

Write it below

HINT:

.If you're stuck you get one hint message me the number and I can give you a key operation to solving it.

Will be written in an hour

EVERYONE:

Everyone can play even if you're late, just don't look into comments :)

...

I reccomend starting in this order: 2, 3, 4, 6, 5, 7, 0, 1, 8

Enjoy, this is just for fun :D

And maths...

1 1 1= 6
2 2 2 = 6
3 3 3 = 6
4 4 4= 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6

Aug 19, 2015

#6
+4682
+13

Spoiler

$$\\(0!+0!+0!)!=6\\\\(1 + 1 + 1)! = 6\\\\(2 + 2 + 2) = 6\\\\(3\times 3-3) = 6\\\\(4-4\div4)! = 6\\\\(5 + 5\div5) = 6\\\\(6 + 6-6) = 6\\\\(7-7\div7) = 6\\\\(\sqrt{(8 + 8\div8)})! = 6\\\\(\sqrt{(9 + 9-9)})! = 6\\\\$$

.
Aug 19, 2015

#1
+1311
+5

MG if powers are not allowed then I cant use square roots and logarithms either right?

Aug 19, 2015
#2
+4682
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You can as long as in the symbol numbers arent shown.

Aug 19, 2015
#3
+1311
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OK I not sure what you mean. I just finish it and send it to you and you can tell me if which ones are not allowed.

Aug 19, 2015
#4
+4682
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Ok then, goodluck!

Aug 19, 2015
#5
+4682
+5

DragonLance has completed it :)

Aug 19, 2015
#6
+4682
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Spoiler

$$\\(0!+0!+0!)!=6\\\\(1 + 1 + 1)! = 6\\\\(2 + 2 + 2) = 6\\\\(3\times 3-3) = 6\\\\(4-4\div4)! = 6\\\\(5 + 5\div5) = 6\\\\(6 + 6-6) = 6\\\\(7-7\div7) = 6\\\\(\sqrt{(8 + 8\div8)})! = 6\\\\(\sqrt{(9 + 9-9)})! = 6\\\\$$

MathsGod1 Aug 19, 2015
#7
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MG  the first one need to have a ! after the last parenthesis.

Aug 19, 2015
#8
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Oh yeah, i forgot thanks.

Aug 19, 2015
#9
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This is really cool MathsGod and and Dragonlance :))

There are a lot of 3! in there

I shall add it to our puzzles.

Aug 19, 2015
#10
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Just strolling through Youtube and found it I enjoyed it a lot too.

Melody, did you get the same results as me?

I guess 3! was the easiest way to get 6.

Aug 19, 2015
#11
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I didn't get them all out - too busy with other things  - that is my excuse and I am sticking with it :))

Aug 19, 2015
#12
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(0!+0!+0!)!=6
(1+1+1)!=6
2+2+2=6
3*3-3=6
√4+√4+√4=6
5/5+5=6
6+6-6=6
7-7/7=6
√(8/8+8)=6
√9*√9-√9=6

Aug 19, 2015
#13
+4682
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Youtube, i didn't see the factorial part i felt so dumb when i didn't realise it but all the answers make sence now :)

I enjoyed it.

Aug 19, 2015
#14
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Check it out, MG ::

(1 + 1 + 1) ! = 3! = 6

(2 + 2 + 2) = 6

(3 + 3 - 3) ! = (3 - 0) ! = (3) ! = 6

(4 + 4 - √4) = (8 - 2) = 6

(5 + 5/5) = (5 + 1) = 6

(7 - 7/7) = (7 - 1 ) = 6

8 - log√8 8 = 8 - 2 = 6

(9 + 9) / √9 = (18)/3 = 6

Aug 19, 2015
#15
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I was watching ASAPScience, then i went into maths question... lol

Aug 19, 2015
#16
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WOW that was very clever of him :))

Aug 19, 2015
#17
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Scratch that.

Aug 19, 2015
#18
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Scratch what?  Are you itchy?    LOL :)

Aug 19, 2015
#19
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No ... Lol

i thought you were referring to ASAPScience but you were talking about CPhill... Lol, so i wrote something else down.

Aug 19, 2015
#20
+95369
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Big smile :D

Aug 19, 2015
#21
+26
0

21   yolo

Feb 24, 2017