+1242 Two sectors of a circle of radius 12 overlap as shown, with P and R as the centers of the respective circles. Determine the area of the shaded region.
+36915 Area of a 60 degree sector of a circle with radius 12 = 60/360 pi 12^2 ------------ there are TWO of these
Minus the area of equalateral triangle sqrt3 /4 12^2 -------------- there are TWO of these
60/360 pi 12^2 * 2 - sqrt3 /4 12^2 *2 = 26.088 sq units
+36915 Area of a 60 degree sector of a circle with radius 12 = 60/360 pi 12^2 ------------ there are TWO of these
Minus the area of equalateral triangle sqrt3 /4 12^2 -------------- there are TWO of these
60/360 pi 12^2 * 2 - sqrt3 /4 12^2 *2 = 26.088 sq units
