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Two sectors of a circle of radius 12 overlap as shown, with P and R as the centers of the respective circles. Determine the area of the shaded region.

 

 Jan 13, 2019

Best Answer 

 #1
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Area of a 60 degree sector of a circle with radius 12  =     60/360 pi 12^2     ------------   there are TWO of these

   Minus the area of equalateral triangle                   sqrt3 /4  12^2             -------------- there are TWO of these

 

60/360 pi 12^2 * 2 -  sqrt3 /4  12^2 *2  =  26.088 sq units

 Jan 13, 2019
edited by ElectricPavlov  Jan 13, 2019
 #1
avatar+25918 
0
Best Answer

Area of a 60 degree sector of a circle with radius 12  =     60/360 pi 12^2     ------------   there are TWO of these

   Minus the area of equalateral triangle                   sqrt3 /4  12^2             -------------- there are TWO of these

 

60/360 pi 12^2 * 2 -  sqrt3 /4  12^2 *2  =  26.088 sq units

ElectricPavlov Jan 13, 2019
edited by ElectricPavlov  Jan 13, 2019

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