+0

# Function Composition Question

0
31
1

Let $$f(x) =\frac {3x^2 + 5x + 8} {x^2 - x + 4 }$$ and $$g(x) = x - 1.$$ Find $$f(g(x)),$$ evaluated when $$x = 1.$$

Guest Feb 21, 2018
Sort:

#1
+84386
+1

f(g(x) =

[ 3 (x - 1)^2 + 5(x - 1) + 8 ] / [ ( x - 1)^2 - (x - 1) + 4 ]

So

f(g(1) )  =

[ 3 (1 - 1)^2 + 5(1 - 1) + 8 ]  / [ (1 - 1)^2 - (1 - 1)  + 4 ] =

[ 3 (0)^2  + 5(0) + 8 ] /  [ (0^2  - 0  + 4 ]  =

]  / [ 0 - 0 + 4 ] =

8 / 4    =   2

CPhill  Feb 21, 2018

### 7 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details