If $t(x) = 9+2f(x)$ and $f(x) = x^2-3$, then what is $t(f(-2))$?
t(x) = 9 + 2 ( x^2 - 3) = 9 + 2x^2 - 6 = 2x^2 + 3
f(-2) = (-2)^2 - 3 = 1
So
t ( f (-2)) = t (1) = 2(1)^2 + 3 = 5
