Suppose a function f(x) has domain (-inf,inf) and range [-11,3]. If we define a new function by

g(x) = 6f(x/2) + 1

then what is the range of g(x)? Express your answer in interval notation.

Guest May 23, 2021

#1**+1 **

\(f(\frac{x}{2})\)has the same range as f(x) since the function is stretched by a factor of 2 horizontally and y values are not affected. \(6f(\frac{x}{2})\), however, has range [6(-11), 6(3)]=[-66, 18], since we are stretching the graph in the y directions by a factor of 6. Finally, we shift the graph up by one unit to get \(6f(\frac{x}{2})+1\) and that transformation changes the range to [-65, 19].

Guest May 24, 2021