+0  
 
0
566
1
avatar
Slove log2(x-1)=log2(2x+1)

Thanks
 Jul 28, 2013
 #1
avatar+259 
0
1 step: concider the range of definition of x, solving the unequaities' system (x-1) > 0, (2x+1)>0

2 step: If logarithms are equal then its numbers are equal too, hence you get the equation (x - 1) = (2x + 1), found roots should be filtered according to the range of definition of x.
 Jul 31, 2013

4 Online Users

avatar
avatar