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# Function

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The number of students enrolled in a new course as a function of time can be represented by the function.

Nov 15, 2017

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f(2)  =  42 - 1   =   16 - 1   =   15           At  2  hours, there are  15  students enrolled.

f(4)  =  44 - 1   =   256 - 1   =   255       At  4  hours, there are  255  students enrolled.

The number of students goes from  15  to  255 .

255 - 15  =  240      So the number of students increased by  240 .

The number of hours goes from  2  to  4 .

4 - 2  =  2      So the number of hours increased by  2 .

In  2  hours time, the number of students increased by  240 .

On average, that is an increase of  240/2  ,  or  120 ,  students per hour.

The average increase in the number of students per hour is  120  .

Nov 15, 2017

#1
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For this, plug values 2 and 4 in for x.

$$f(2)=(4)^2-1, f(4)=(4)^4-1$$

$$f(2)=16-1, f(4)=256-1$$

$$f(2)=15, f(4)=255$$

For the average, add the two values and divide by 2.

$$\frac{15+255}{2}=\frac{270}{2}=135$$

So the average increase is 135 students.

Nov 15, 2017
#2
+7348
+1

f(2)  =  42 - 1   =   16 - 1   =   15           At  2  hours, there are  15  students enrolled.

f(4)  =  44 - 1   =   256 - 1   =   255       At  4  hours, there are  255  students enrolled.

The number of students goes from  15  to  255 .

255 - 15  =  240      So the number of students increased by  240 .

The number of hours goes from  2  to  4 .

4 - 2  =  2      So the number of hours increased by  2 .

In  2  hours time, the number of students increased by  240 .

On average, that is an increase of  240/2  ,  or  120 ,  students per hour.

The average increase in the number of students per hour is  120  .

hectictar Nov 15, 2017