+912 
The number of students enrolled in a new course as a function of time can be represented by the function.
+9479 f(2) = 42 - 1 = 16 - 1 = 15 At 2 hours, there are 15 students enrolled.
f(4) = 44 - 1 = 256 - 1 = 255 At 4 hours, there are 255 students enrolled.
The number of students goes from 15 to 255 .
255 - 15 = 240 So the number of students increased by 240 .
The number of hours goes from 2 to 4 .
4 - 2 = 2 So the number of hours increased by 2 .
In 2 hours time, the number of students increased by 240 .
On average, that is an increase of 240/2 , or 120 , students per hour.
The average increase in the number of students per hour is 120 .
+895 For this, plug values 2 and 4 in for x.
\(f(2)=(4)^2-1, f(4)=(4)^4-1\)
\(f(2)=16-1, f(4)=256-1\)
\(f(2)=15, f(4)=255\)
For the average, add the two values and divide by 2.
\(\frac{15+255}{2}=\frac{270}{2}=135\)
So the average increase is 135 students.
+9479 f(2) = 42 - 1 = 16 - 1 = 15 At 2 hours, there are 15 students enrolled.
f(4) = 44 - 1 = 256 - 1 = 255 At 4 hours, there are 255 students enrolled.
The number of students goes from 15 to 255 .
255 - 15 = 240 So the number of students increased by 240 .
The number of hours goes from 2 to 4 .
4 - 2 = 2 So the number of hours increased by 2 .
In 2 hours time, the number of students increased by 240 .
On average, that is an increase of 240/2 , or 120 , students per hour.
The average increase in the number of students per hour is 120 .
