The function f(\sqrt{x + 1}) = \frac{1}{x + 1} satisfies for all $x \ge -1,$ Find f(2).
\(f(\sqrt{x + 1}) = \frac{1}{x + 1}\)
Note that : f ( sqrt (3 + 1) ) = f ( sqrt ( 4) ) = f (2)
So
1 1
f(2) = _____ = ____
3 + 1 4
