Let
f(x) = 2x + 1 if x <= 3
f(x) = 8 - x if x > 3
Find the sum of all values of x such that f(x)=0
+36916 2x+1 = 0 solve for 'x' to see if <=3
x = -1/2 this is one solution
8-x =0
8 = x this is >3 so this is the second solution..... add them together
