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Let f(x) be defined by

f(x) = 3 - x if x <= 3

f(x) = x^2 - 6x + 9 if x > 3

 

Calculate f(0) + f(6).

 May 21, 2022
 #1
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This problem is not that hard. 

It asks if "x" is less than or equal to 3 then plug in the first equation and if "x" is greater than 3 then plug in the second equation.

 

f(0) = 3-x = 3-0 = 3

f(6) = x^2-6x+9 = 9

 

f(0) + f(6)

3 + 9 = 12

 

Hope this helped!!

 May 21, 2022

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