Let f(x) be defined by
f(x) = 3 - x if x <= 3
f(x) = x^2 - 6x + 9 if x > 3
Calculate f(0) + f(6).
+589 This problem is not that hard.
It asks if "x" is less than or equal to 3 then plug in the first equation and if "x" is greater than 3 then plug in the second equation.
f(0) = 3-x = 3-0 = 3
f(6) = x^2-6x+9 = 9
f(0) + f(6)
3 + 9 = 12
Hope this helped!!
