Let f(x) be defined by

f(x) = 3 - x if x <= 3

f(x) = x^2 - 6x + 9 if x > 3

Calculate f(0) + f(6).

Guest May 21, 2022

#1**0 **

This problem is not that hard.

It asks if "x" is less than or equal to 3 then plug in the first equation and if "x" is greater than 3 then plug in the second equation.

f(0) = 3-x = 3-0 = 3

f(6) = x^2-6x+9 = 9

f(0) + f(6)

3 + 9 = 12

Hope this helped!!

weredumbmaster22 May 21, 2022