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If t(x) = 3 - g(x) and g(x) = x^2, then what is t(g(16))?

 Dec 23, 2020

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t(g(16)) = 3-(16^2)^2

 Dec 23, 2020

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 #1
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Best Answer

t(g(16)) = 3-(16^2)^2

Guest Dec 23, 2020

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