+0  
 
0
77
1
avatar

If t(x) = 3 - g(x) and g(x) = x^2, then what is t(g(16))?

 Dec 23, 2020

Best Answer 

 #1
avatar
+1

t(g(16)) = 3-(16^2)^2

 Dec 23, 2020
 #1
avatar
+1
Best Answer

t(g(16)) = 3-(16^2)^2

Guest Dec 23, 2020

15 Online Users

avatar
avatar