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Rewrite 2x^2+9x-5 in factored form then find x-intercepts and vertex and graph the function

 Mar 30, 2016
 #1
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+5

Here is your quadratic equation factored:

Factor the following:
2 x^2+9 x-5

Factor the quadratic 2 x^2+9 x-5. The coefficient of x^2 is 2 and the constant term is -5. The product of 2 and -5 is -10. The factors of -10 which sum to 9 are -1 and 10. So 2 x^2+9 x-5  =  2 x^2+10 x-x-5  =  5 (2 x-1)+x (2 x-1):
5 (2 x-1)+x (2 x-1)

Factor 2 x-1 from 5 (2 x-1)+x (2 x-1):
Answer: |  (2 x-1) (x+5)

 

Now, to graph it, go to this link and learn how to use the graphing calculator there:https://www.desmos.com/calculator.

Good luck to you.

 Mar 30, 2016
 #2
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0

Solve using the quadratic formula:

 

A) 5x^2+7x=-2                              B) 12x^2-28x+15=0

 Mar 30, 2016

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