+4620 If \(f(3)=1\) and \(f(2x)=2f(x)\) for all \(x\) , find \(f^{-1}(64)\).
+129845 f(3) = 1
f(6) = f(2 * 3) = 2f(3) = 2 * 1 = 2
f(12) = f(2 * 6) = 2f(6) = 2 * 2 = 4
f(24) = f(2 * 12) = 2f(12) = 2 * 4 = 8
f(48) = f(2 * 24)= 2f(24) = 2 * 8 = 16
f(96) = f(2 *48) = 2f(48) = 2 * 16 = 32
f(192) = f(2 * 96) = 2f(96) = 2 * 32 = 64
So
f(192) = 64 which implies that
f-1(64) = 192
