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avatar+149 

\(\sqrt[4]{4096a^{8}b^{20}}\)

 

\(\sqrt{72x^{12}y^{4}}\)

 Jan 10, 2020
 #1
avatar+107405 
+1

4√[4096a8b20 ]  =  4 √[ 212a8b20 ]  =   (2^12 )^(1/4)  * (a^8)^(1/4)  * (b^20)^(1/4)  =  2^3 * a^2 * b^5  =

 

8a2b5

 

 

√ [ 72 x12 y 4 ] =  √ [ 36 * 2 ] *(x^12)^(1/2) * (y^4)^(1/2)  =   √2  * √36  * x6 * y2  =

 

 

√2  *  6  x6y2   =

 

6x6y2 √2

 

 

 

cool cool cool

 Jan 10, 2020
 #2
avatar+149 
+2

Thank you

BabyChimChim  Jan 10, 2020

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