\(\sqrt[4]{4096a^{8}b^{20}}\)
\(\sqrt{72x^{12}y^{4}}\)
4√[4096a8b20 ] = 4 √[ 212a8b20 ] = (2^12 )^(1/4) * (a^8)^(1/4) * (b^20)^(1/4) = 2^3 * a^2 * b^5 =
8a2b5
√ [ 72 x12 y 4 ] = √ [ 36 * 2 ] *(x^12)^(1/2) * (y^4)^(1/2) = √2 * √36 * x6 * y2 =
√2 * 6 x6y2 =
6x6y2 √2
Thank you
