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What is the range of the function $$r(x) = \frac{1}{(1-x)^2}~?$$ Express your answer in interval notation.

Guest Jul 10, 2018
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$$r(x) = \dfrac{1}{(1-x)^2}$$

When x -> 1, r-> infinity. So the maximum value of r(x) is +infinity.

Now we just have to find the minimum value of r(x).

Horizontal asymptote of r(x) is y = 0, which means the r(x) is approaching 0 when x approachs +inf or -inf.

Therefore range of r(x) is (0, inf).

MaxWong  Jul 15, 2018