+0  
 
0
294
1
avatar

What is the range of the function $$r(x) = \frac{1}{(1-x)^2}~?$$ Express your answer in interval notation.

 Jul 10, 2018
 #1
avatar+7763 
+1

\(r(x) = \dfrac{1}{(1-x)^2}\)

When x -> 1, r-> infinity. So the maximum value of r(x) is +infinity.

Now we just have to find the minimum value of r(x).

Horizontal asymptote of r(x) is y = 0, which means the r(x) is approaching 0 when x approachs +inf or -inf.

Therefore range of r(x) is (0, inf).

 Jul 15, 2018

31 Online Users