For the function f(x)=x^2+5x-24 solve the following. f(x)_<0
(x-3) (x+8) = f(x)
x = -8 and x = 3
As "Guest" has said, the roots of this polynomial are at x = -8 and x = 3
I think the question is, "Where is the polynomial < 0 ??"
The solution is the interval [-8, 3 ]
