Let
f(x) = 2x + 5
g(x) = sqrt(f(x)) - 3
h(x) = f(g(x))
What is h(2)?
h(2) = f( g(2) )
g(2) = sqrt( f(2) ) - 3
f(2) = 2(2) + 5 - 4 + 5 = 9
---> g(2) = sqrt( 9 ) - 3 = 3 - 3 = 0
---> h(2) = f( 0 ) = 2(0) + 5 = 0 + 5 = 5