Let
f(x) = ax + 3 if x > 2
f(x) = x + 5 if -2 <= x <= 2
f(x) = 2x - b if x <= -2
Find a+b if the piecewise function is continuous
At x = 2, x + 5 = 7
If continuous ,then
a (2) + 3 = 7
2a = 4
a = 2
Also
At x = -2 , x+ 5 = 3
If continuous, then
2(-2) - b = 3
-4 - b = 3
-4 -3 = b
-7 = b
So
a + b = 2 - 7 = -5
srry was out for a min
