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Mary stands on a balcony. Joe is on the left of the balcony looking up at her at an angle of 52 with the ground. Trent is on the right of the balcony looking up at her at an angle of 47 with the ground.  If the height, h, is 4 m, how far apart are Joe and Trent standing to the nearest tenth of a metre? Assume the angle the base of the balcony makes between Joe and Trent is 90.

 May 5, 2022
 #1
avatar+124595 
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I'm assuming that the height of th balcony is  4m

 

So....the distance between them  is  given by

 

4 /tan (52°)   +  4/tan 47°)   ≈   6.86 ft

 

 

cool cool cool

 May 5, 2022

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