The function f(n)=3f(n-2)-2f(n-1), where f(2)=3 and f(1)=-1. What is the value of f(5)?
\(f(5) = 3f(3)-2f(4)\\ f(3) = 3f(1)-2f(2) = -3 - 2(3) = -9\\~\\ f(4) = 3f(2)-2f(3) = 3(3) - 2(-9) = 27\\~\\ f(5) = 3(-9) - 2(27) = -81\)
+37 
