The function f(n)=3f(n-2)-2f(n-1), where f(2)=3 and f(1)=-1. What is the value of f(5)?
f(5)=3f(3)−2f(4)f(3)=3f(1)−2f(2)=−3−2(3)=−9 f(4)=3f(2)−2f(3)=3(3)−2(−9)=27 f(5)=3(−9)−2(27)=−81
+37 
