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Keep getting the last 2 wrong:(

 

 Sep 18, 2019
 #1
avatar+19822 
+2

g(a-6)      put in   'a-6'   for 'x' in the g function

 

[6-(a-6)] / [6+(a-6)] = (12-a)/a   

 

For the last one  sub in   x^2-6     for   'x' in the  g function and see what you find.....

 Sep 18, 2019
 #2
avatar+104869 
+2

g (x^2 - 6)   =   6  -  (x^2 - 6)                 12 - x^2

                       _____________  =       _______

                         6 +  (x^2  - 6)                    x^2

 

 

 

cool cool cool

 Sep 19, 2019

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