functions

c(2,12,3) = \(\frac{2}{12} + \frac{12}{3} + \frac{3}{2}\)

               = \(\frac{1}{6} + \frac{24}{6} + \frac{9}{6}\)

               = \(\frac{34}{6}\)

               = \(\frac{17}{3} \) or \(5\frac{2}{3}\)

Plugging in, you get $\frac{2}{12}+\frac{12}{3}+\frac{3}{2}=\frac{1}{6}+4+\frac{3}{2}=4+\frac{1}{6}+\frac{9}{6}=4+\frac{10}{6}=4+\frac{5}{3}=\boxed{\frac{17}{3}}$