functions

if P=(2^a)(b), f(P)=2^-a,
then find f(n^3-2n^2+n) for n=even and positive integer.

This is an odd question but here goes.

P=2 ^ab ==> 2 ^a = P/b ==> 2 ^-a = b/P (P<>0 and b<>0)
So
f(P) = 2 ^-a = b/P

f(n ³-2n ²+n)

= b/ ( n ³-2n ²+n )

= b / [n(n-1) ²] where n<> 0 or 1

This is fine since n = an even and positive integer.

I think it is finished now.