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A cannon ball has been catapulted through the air and follows the path created by the function f(t)= -16t^2+30t+7 where f(t) is the height of the cannonball in meters at any given time (t) in seconds.

 

1. What is the initial height (y-intercept) the cannon ball was launched from?   I know this one is 7

2. When will the cannon ball hit the ground (x-intercept)? Round to the nearest tenth.   

3. What is the cannon ball’s maximum height? Round to the nearest tenth.   

 Mar 2, 2023
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This is a quadratic equation, so we can solve for all of this with a graph!


sorry i cant include an image but you can graph it yourself on desmos or some other calculator

the initial height is 7 (we see this from the equation, the c therm is the y intercept (initial height))

the cannonball will hit the ground at the positive x intercept, which is (2.1,0)

the maximum height is (0.9,21.1)


hope this helps!

 Mar 2, 2023

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