g(x)=4(x-3)^2+1 find g(-2)

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Guest Jan 25, 2015

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Best Answer

$$\\g(x)=4(x-3)^2+1 find g(-2)\\\\
g(-2)=4(-2-3)^2+1 \\\\
g(-2)=4(-5)^2+1 \\\\
g(-2)=4(25)+1 \\\\
g(-2)=100+1 \\\\
g(-2)=101 \\\\$$

Melody Jan 26, 2015

Melody · Answer 1 · 2015-01-26T09:31:54

$$\\g(x)=4(x-3)^2+1 find g(-2)\\\\
g(-2)=4(-2-3)^2+1 \\\\
g(-2)=4(-5)^2+1 \\\\
g(-2)=4(25)+1 \\\\
g(-2)=100+1 \\\\
g(-2)=101 \\\\$$

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