g(x)=x/5+1
find g^-1(x)
explain how please
g(x) = x/5 + 1
Write as
y = x/5 + 1 subtract 1 from each side
y - 1 = x/5 multiply both sides by 5
5 ( y - 1) = x simplify
5y - 5 = x "swap" x and y
5x - 5 = y for y, write g-1 (x)
5x - 5 = g-1 (x)