+586 When the greatest common divisor and least common multiple of two integers are multiplied, the product is 180. How many different values could be the greatest common divisor of the two integers?
+118687 When the greatest common divisor and least common multiple of two integers are multiplied, the product is 180. How many different values could be the greatest common divisor of the two integers?
Let the numbers be ax and ay where x and y are relatively prime and a, x, and y are all positive integers.
So the GCD is \(a\)
and the lowest commone multiple is axy
The product of these is \(a^2xy\)
So we have
\(a^2xy=180\\ a^2 \;\;must \;\;be\;\;1,4,9, or \; 36 \;\text{no other square integerwill make this true}\\ \text{So a = 1, -1, 2, -2, 3,- 3, 6 or - 6}\\ \)
So there seems to be 8 possible values for the greatest common divisor.
