Find the maximum value of \(f(x,y) = x \sqrt{1 - y^2} + y \sqrt{1 - x^2}\) , where \( -1 \le x, y \le 1 \).

Guest Oct 27, 2019

#3**+1 **

This is not the answer you need but

if y=0 and x=1 (or vise versa) then the function value is 1

So the minimum value is greater or equal to 1.

Melody Oct 28, 2019