+0  
 
+2
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avatar+604 

In triangle \(\triangle XYZ\) , we have \(\angle Z = 90^\circ\)\(XY = 10\), and \(YZ = \sqrt{51}\). What is \(\tan X\)?

mathtoo  Mar 6, 2018
 #1
avatar+88871 
+3

Best to draw  a  "mock" pic

 

 

x

         10

 

z     √51             y

 

We need to find  xz  =    √ [ 10^2  - 51  ]  =  √  [ 100 - 51 ] =  √ 49  = 7

 

So....tan  X    =  zy / xz  =  √51  / 7

 

 

cool cool cool

CPhill  Mar 6, 2018
 #2
avatar+604 
+1

Thanks so much, CPhill! smiley

mathtoo  Mar 6, 2018
 #3
avatar+88871 
+1

No prob... MT   !!!

 

 

cool cool cool

CPhill  Mar 6, 2018

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