In triangle \(\triangle XYZ\) , we have \(\angle Z = 90^\circ\), \(XY = 10\), and \(YZ = \sqrt{51}\). What is \(\tan X\)?
Best to draw a "mock" pic
x
10
z √51 y
We need to find xz = √ [ 10^2 - 51 ] = √ [ 100 - 51 ] = √ 49 = 7
So....tan X = zy / xz = √51 / 7
Thanks so much, CPhill!
No prob... MT !!!
+816 
