In triangle ABC, CA = 4sqrt2, CB = 4sqrt3, and angle A = 45 degrees. What is B in degrees?
+128474 CA = b = side opposite angle B
CB = a = side opposite angle A
Using the Law of Sines
sin B / b = sin A / a
sin B / (4sqrt (2) ) = sin A / (4sqrt (3))
sin B / (4 sqrt (2)) = sin 45° / (4sqrt (3))
sin B / (4sqrt (2)) = (1/sqrt (2) ) / (4sqrt (3))
sin B = (4sqrt (2) ) / (4sqrt (3)) * (1 /sqrt (2) )
sin B = 1/ sqrt (3)
arcsin (1/sqrt (3)) = B ≈ 35.26°
