What is the area of a triangle with altitudes of length 3, 4, and 5?
Using Heron's formula: √s(s-a)(s-b)(s-c), we can calculate this easily :) s = semiperimeter = (3 + 4 + 5) / 2 = 6 √s(s-a)(s-b)(s-c) = √6(6-3)(6-4)(6-5) = 6 units2, which is your answer :)
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