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We have two geometric sequences of positive real numbers:

6,a,b and a,b,54

Solve for a

 Nov 22, 2020
 #1
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We have two geometric sequences of positive real numbers:     

6,a,b and a,b,54     

Solve for a      

 

6               =  1st  term     

6 • r           =  2nd  term ... this is a     

6 • r • r      =  3rd  term ... this is b     

6 • r • r • r  =  4th  term ... this is 54     

 

so                 6r3  =  54    

                       r3  =  9     

                       r    =  cube root of 9     

 

a  =  6 r  =  6 cbrt(9)     

 

This is about 12.48 but that's just a close approximation.   

.     

 Jul 31, 2025

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