We have two geometric sequences of positive real numbers:
6,a,b and a,b,54
Solve for a
We have two geometric sequences of positive real numbers:
6,a,b and a,b,54
Solve for a
6 = 1st term
6 • r = 2nd term ... this is a
6 • r • r = 3rd term ... this is b
6 • r • r • r = 4th term ... this is 54
so 6r3 = 54
r3 = 9
r = cube root of 9
a = 6 • r = 6 • cbrt(9)
This is about 12.48 but that's just a close approximation.
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