Find the fifth term of the geometric sequence with first term 2 and second term 1/7.
So first you can tell that each term after the first is mutiplied by \(1\over14\) because \(1\over7\)\(\div\)2=\(1\over14\)
Thus you can do \(2 \times \)\(1\over14\)4
You get \(2\times\)\(1\over38416\)
Simplified, it gives you \(1\over19208\)