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Find the fifth term of the geometric sequence with first term 2 and second term 1/7.

 Jan 6, 2021
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So first you can tell that each term after the first is mutiplied by \(1\over14\) because \(1\over7\)\(\div\)2=\(1\over14\)

Thus you can do \(2 \times \)\(1\over14\)4

You get \(2\times\)\(1\over38416\)

Simplified, it gives you \(1\over19208\)

 Jan 6, 2021

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