+0  
 
0
89
2
avatar

Consider the geometric sequence 3, 3/2, 3/4, 3/8, ... . Find the eighth term of the sequence. Express your answer as a common fraction.

 Jan 6, 2021
 #1
avatar+536 
0

3/128

The denominator is two two the (x-1) power (x is the position in th sequence)

8-1=7

2^7=128

 Jan 6, 2021
 #2
avatar+218 
0

You could write out every term 3, 3/2, 3/4, 3/8, 3/16, 3/32, 3/64, 3/128

OR

Use the formula a*r^(n-1) where a is the first term, r is the ratio and n is the term you are solving for.

So 3*1/2^7 so you get 3/128

:D

 Jan 6, 2021

17 Online Users

avatar