Consider the geometric sequence 3, 3/2, 3/4, 3/8, ... . Find the eighth term of the sequence. Express your answer as a common fraction.
3/128
The denominator is two two the (x-1) power (x is the position in th sequence)
8-1=7
2^7=128
You could write out every term 3, 3/2, 3/4, 3/8, 3/16, 3/32, 3/64, 3/128
OR
Use the formula a*r^(n-1) where a is the first term, r is the ratio and n is the term you are solving for.
So 3*1/2^7 so you get 3/128
:D
+539 
