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Find the 7th term of sqrt(2), sqrt(10), 5*sqrt(2), ...

 Feb 16, 2021
 #1
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√2, √10, 5√2...

 

5√2 = √(2 * 52) = √50

 

The pattern is multiplying by 5 inside the square root.

 

To find the nth term, it would be:  nth term = √(2 * 5(n - 1))

 

This means the 7th term = √(2 * 5(7 - 1))

                                        = √(2 * 56)

                                        = √(2 * 15625)

                                        = √31250, which is your answer :)

 Feb 16, 2021

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