+0  
 
0
58
1
avatar

How many terms are in the geometric sequence?
\[3, 3 \sqrt 2, 6, \dots, 96, 96 \sqrt 2, 192, \dots, 768, 768 \sqrt{2}\]

 May 14, 2022
 #1
avatar+9457 
0

Common ratio = (second term)/(first term) = \(\dfrac{3\sqrt2}3 = \sqrt2\)

 

Therefore, if the nth term of the sequence is \(768\sqrt 2\), then \(3\left(\sqrt 2\right)^{n - 1} = 768\sqrt 2\)

 

Then \(\left(\sqrt 2\right)^n = 512\).

 

You can calculate the value of n, and 768 sqrt(2) will be the nth term, i.e., there are n terms in the sequence, which I will leave it for you to calculate.

 May 14, 2022
edited by MaxWong  May 14, 2022

7 Online Users