Let \(S = \frac{1}{2^3} + \frac{1}{4^3} + \frac{1}{6^3} + \dotsb\)
And \(T = \frac{1}{1^3} + \frac{1}{3^3} + \frac{1}{5^3} + \dotsb.\)
Find S/T
S =sumfor(n, 1,∞ , (1/(2*n)^3))=0.1502570505........ T =sumfor(n, 1,∞ , (1/(2*n -1)^3))=1.051799728....... S/T =0.1502570505 / 1.051799728 =1 /7
Which is the same as:
∑[(1/(2*n)^3)), n, 1, ∞] / ∑[(1/(2*n - 1)^3)), n , 1, ∞] = 1/7
+49 
