+0  
 
0
82
1
avatar

Find the sum of the first six terms of the geometric sequence 1/2, 1/6, 1/18, ... Express your answer as a common fraction.

 May 5, 2022
 #1
avatar+124595 
+1

Sum   = 

 

first term  [  1 - common ratio ^n ]   / [ 1  -common  ratio]

 

Where 

first term  1/2

common  ratio  =  1/3

n  = the  number of  summed terms

 

So

 

(1/2) [ 1 - (1/3)^6] / [ 1  -1/3 ]   =

 

(3/4) [ 1 - (1/3)^6]  =

 

182 / 243

 

cool cool cool

 May 5, 2022

33 Online Users