Find the value of b given that b/7+b^2/7^2+b^3/7^3.....=1
Sum of an infinite series =
[ First term ] / [ 1 -common ratio]
common ratio = 1/7
(b/7) / [ 1 - 1/7 ] = 1
(b/7) / (6/7) = 1
b / 6 = 1
b = 6