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# /gone

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Dec 13, 2019
edited by whoisjoe  Dec 14, 2019
edited by whoisjoe  Jan 7, 2020

### 13+0 Answers

#1
0

1. Angle RPB is 72 degrees

2. Arc POQ is 220 degrees.

3. Angle ABC is 135.5 degrees.

Dec 13, 2019
#2
+30
-2

I'm sorry, these answers are incorrect

whoisjoe  Dec 13, 2019
#3
+30
-2

Does anyone have the correct answers for these?

Dec 13, 2019
#4
0

Problem 1: Since AR = AB, triangle ARB is isosceles.  Also, arc AB is 130 degrees, so angle ARB is 130/2 = 65 degrees, which means angle RAB is also 65 degrees.  Then arc RB is 130 degrees.  Since arc AQ is 28 degrees, angle RPB is (130 + 28)/2 = 79 degrees.

Problem 2: Since arc POQ is 80 degrees, angle POQ is 160 degrees.  Then major arc PQ is 360 - 160 = 200 degrees, so arc POQ on the smaller circle is (360 - 200) + 80 = 240 degrees.

Problem 3: Angle ABX = Angle AOX = 35 degrees, so Angle ABC = 180 - 35 = 145 degrees.

Guest Dec 13, 2019
#5
+30
-2

These answers are also incorrect.

whoisjoe  Dec 13, 2019
#6
0

Why are you asking all these problems?  Is this homework?

Dec 13, 2019
#7
+108626
0

The multiple questions are asked because the whoisjoe is lazy

And the answers are responded to in this  way because whoisjoe is rude and ungrateful and also because whoisjoe is too lazy to give the reason for his/her assertion.

Melody  Dec 13, 2019
#8
0

What have you actually tried?

And why is this so "urgent"?  Are you just trying to get us to do your homework for you?

Dec 13, 2019
#9
+109064
+1

First one

Connect RB

Then.....since   AR   = AB..... then   in triangle  ARB, angle ARB  = angle  ABR

And  if  arc AB  = 130   then angle  ARB  = 130/2  =  65°   =  angle  ABR

So  angle  RAB  = angle PAB =   180 -130  =  50°

And since arc AQ = 28, then angle QBA  =  angle PBA  =  14°

So by the exterior angle theorem  angle  RPB  = angle PAB +angle PBA =  50 + 14  =  64°

Dec 13, 2019
#10
+109064
+1

Second one

Since  in the larger circle, minor arc PQ  =  80  degrees

Then central angle POQ   also  = 80°

But if angle POQ  = 80°, then, in the smaller circle..... minor arc PQ  =  160°

Then arc POQ  =  360 -160   =  200°

Dec 13, 2019
#11
+109064
+1

Third one

Since minor arc  AX  = 35°,then angle AYX  =  35/2  = 17.5°

And since minor arc CY  = 80°, hen angle CXY  = 80 / 2  = 40°

Then  in triangle XBY, angle XBY = 180  -  17.5 - 40   =  122.5°

And angle  ABC  is vertical to angle  XBY....so its measure is also 122.5°

Dec 13, 2019
#12
0

Why did you delete the problems you originally posted?

Dec 15, 2019
#13
+108626
0

Because whoisjoe is a rude ungrateful cheat.   I already told you that.

He is attempting his tracks so that his teacher will not notice.

Melody  Dec 15, 2019
edited by Melody  Dec 15, 2019