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Trapezoid $EFGH$ is inscribed in a circle, with $EF \parallel GH$. If arc $GH$ is $70$ degrees, arc $EH$ is $x^2 - 2x$ degrees, and arc $FG$ is $56 - 3x$ degrees, where $x > 0,$ find arc $EPF$, in degrees.

 Feb 3, 2020
 #1
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Arc EPF is 205 degrees.

 Feb 3, 2020
 #3
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Thank you!

Guest Feb 4, 2020
 #2
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I almost never look at questions with unnecessary $ signs. It shows me how lazy the asker is. 

 Feb 3, 2020

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