In the diagram below, A is on line segment CE and AB bisects Angle DAC. If segment DA is parallel to segment EF and angle AEF = 10angleBAC - 12 degrees, then what is angle DAC in degrees?

diagram:

I'm not quite sure on how to solve this, a push in the right direction would be helpfil! Thank you!

Guest Apr 29, 2021

#1**+1 **

∠DAC + ∠AEF = 180º

∠DAB = ∠BAC

∠BAC = (∠DAC + ∠AEF + 12) / 12

∠BAC = 16º

∠DAC = 32º

civonamzuk Apr 29, 2021