In the diagram below, A is on line segment CE and AB bisects Angle DAC. If segment DA is parallel to segment EF and angle AEF = 10angleBAC - 12 degrees, then what is angle DAC in degrees?
diagram:
I'm not quite sure on how to solve this, a push in the right direction would be helpfil! Thank you!
+1694 ∠DAC + ∠AEF = 180º
∠DAB = ∠BAC
∠BAC = (∠DAC + ∠AEF + 12) / 12
∠BAC = 16º
∠DAC = 32º
