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In the diagram below, A is on line segment CE and AB bisects Angle DAC. If segment DA is parallel to segment EF and angle AEF = 10angleBAC - 12 degrees, then what is angle DAC in degrees?

 

diagram:

 

 

I'm not quite sure on how to solve this, a push in the right direction would be helpfil! Thank you!

 Apr 29, 2021
 #1
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∠DAC + ∠AEF = 180º

 

∠DAB = ∠BAC 

 

∠BAC = (∠DAC + ∠AEF + 12) / 12

 

∠BAC = 16º

 

∠DAC = 32º

 Apr 29, 2021

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