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can someone please guide me thru this? thank you so much

 Oct 1, 2018
 #1
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\(180^\circ \text{ is the sum of the interior angles of a triangle}\\ x = 180-42=73 = 65\\ \text{the sum of supplementary angles is }180^\circ \\ y = 180 - 131 = 49 \\ \text{Now z is supplementary to the unlabeled angle that is }180-x-y \\ \text{thus }z = 180 - (180-x-y) = x+y \\ z = 65 + 49 = 114^\circ\)

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 Oct 2, 2018

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