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Let G be the center of equilateral triangle XYZ. A dilation centered at G with scale factor -4/3 is applied to triangle XYZ to obtain triangle X'Y'Z' Let A be the area of the region that is contained in both triangles XYZ and X'Y'Z' Find A/[XYZ].

 

Thanks so much!

 Mar 1, 2021
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It works out to A/[XYZ] = 17/27.

 Mar 2, 2021

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