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avatar+45 

Find the area of the triangle. [asy] unitsize(1 cm); pair A, B, C; A = (1,2); B = (0,0); C = (4,0); draw(A--B--C--cycle); label("$\frac{4}{3}$", (A + B)/2, NW, red); label("$2$", (A + C)/2, NE, red); label("$\frac{8}{3}$", (B + C)/2, S, red); [/asy]

 May 4, 2024
 #1
avatar+1234 
0

The area of the triangle is 7*sqrt(2)/2.

 May 4, 2024

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