Two long strips of paper are each $2$ inches wide, and they overlap so that the angle between the strips is $20^{\circ}$. What is the number of square inches in the area of the parallelogram formed by the overlap?
The area of overlap is 13/8.
Here is a good start
Area = 2a+2b
tan 20 = 2/b and sin20=2/(a+b)
solve simultaneously then substitute
