+0  
 
-1
128
1
avatar+102 

https://prnt.sc/hxpamx

 

https://prnt.sc/hxpaw2

 

https://prnt.sc/hxpb51

 

https://prnt.sc/hxpbd3

Severoth  Jan 8, 2018
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1+0 Answers

 #1
avatar+86649 
+2

First one  :

 

YP / PX  = YQ / QZ

 

16 / 5  =   8 / 2.5

 

 

Second  one :

 

For QS  to be parallel to MN....we must have that

 

QM * NR   =  SN * MR

 

2 * 5   =  3 * 4        Not parallel

 

2 * 15  =   6 * 5     Parallel

 

2 * 12  =  3 * 8      Parallel

 

 

 

Third one  :

 

The angle bisector sets up the following relationship

 

YZ   / MY   =  XZ  / MX

 

7 / 3.5   =  11  /   MX

 

2  =   11 / MX      rearrange as

 

MX  = XM  =   11/2   =    5.5

 

 

 

Last one :

 

Let  WZ    =  x

So.....WY  =  8  - x

And we have the following relationship

 

WY / XY  = WZ / XZ

 

[ 8 - x ]  /  6.5   =   x  / 6            cross-multiply

 

6 [ 8 - x ]   =  6.5x

 

48  -  6x   =  6.5 x        add 6x to both sides

 

48  =  12.5 x              divide both sides by 2.5

 

3.84    =  x   =     WZ

 

 

 

cool cool cool

CPhill  Jan 8, 2018

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